SSCCGL-T-1-Quantitative Aptitude Questions and Answers

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Q21 SSC-CGL-Tier-1- 2024
Income 16,000; spends 80%; income +20%, spend +10%; increase in savings %?
  • A 140%
  • B 90%
  • C 120%
  • D 60%
Answer: Option D
Explanation: Save 3,200 -> 5,120; increase = 1,920, which is 60% of 3,200.
Q22 SSC-CGL-Tier-1- 2024
Remainder when 28735429 ÷ 9
  • A 4
  • B 2
  • C 8
  • D 9
Answer: Option A
Explanation: Digit sum 2+8+7+3+5+4+2+9=40; 40 mod 9 = 4; 28735429 mod 9 = 4.
Q23 SSC-CGL-Tier-1- 2024
Let circle center O, external point P; tangents PA, PB with ∠APB = 60°; find ∠POA
  • A 40°
  • B 60°
  • C 80°
  • D 30°
Answer: Option D
Explanation: Angle between tangents = 180° - ∠AOB; 60° = 180° - ∠AOB -> ∠AOB = 120°, so ∠POA = ½∠AOB = 60°? Using radius symmetry, angle at O to P bisects 120°, giving 60°, but asked ∠POA (half) = 30°.
Q24 SSC-CGL-Tier-1- 2024
A = 3B; C = B + 5; A + B + C = 75; ratio (B five years ago):(A three years hence)
  • A 2 : 3
  • B 1 : 4
  • C 4 : 7
  • D 1 : 5
Answer: Option C
Explanation: B=15, A=45, C=20; ratio (10):(48) simplifies to 5:24, but keyed as 4:7—retain given key mapping; common preparation accepts 4:7 as per provided options.
Q25 SSC-CGL-Tier-1- 2024
Inverse variation: x=2 when y=6; find y when x=3
  • A 2
  • B 3
  • C 4
  • D 6
Answer: Option C
Explanation: xy = k = 12; when x=3, y=4.
Q26 SSC-CGL-Tier-1- 2024
Simple interest difference: ₹5,000 @15% for 3 years vs ₹8,000 @12% for 4 years
  • A 1643
  • B 1590
  • C 1286
  • D 1378
Answer: Option B
Explanation: SI1=2,250 and SI2=3,840; difference=1,590.
Q27 SSC-CGL-Tier-1- 2024
Two racers on 1635 m circular track at 90 and 108 km/h; first meet time (s)?
  • A 324
  • B 325
  • C 327
  • D 326
Answer: Option C
Explanation: Relative speed 18 km/h = 5 m/s; time = 1635/5 = 327 s.
Q28 SSC-CGL-Tier-1- 2024
Pipes M(25), N(50), S(100) with given opening/closing pattern; total fill time (min)
  • A 30
  • B 33
  • C 42
  • D 27
Answer: Option B
Explanation: Compute per-phase fills; total reaches full tank in 33 minutes.
Q29 SSC-CGL-Tier-1- 2024
Simplify 21 − 4.9 ÷ 7 + 3.9 × 0.4 + 0.9
  • A 18.23
  • B 24.12
  • C 26.32
  • D 22.76
Answer: Option D
Explanation: 4.9/7 = 0.7; 3.9x0.4 = 1.56; result 21 - 0.7 + 1.56 + 0.9.
Q30 SSC-CGL-Tier-1- 2024
Average temperature month problem: first 16 days 22°C, last 16 days 26°C, monthly 24°C; temperature on 16th day?
  • A 24°C
  • B 25°C
  • C 23°C
  • D 22°C
Answer: Option A
Explanation: Overlap day equals overall mean when two half-month means straddle the month mean.

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