Math Quantitative Aptitude MCQ
Math Quantitative Aptitude MCQ
31. The conjugate of a complex number is 1/i-1. Then the complex number is
- -1/i-1
- 1/i+1
- 1/i-1
- -1/i+1
32. Let R be the real line. Consider the following subsets of the plane R × R. S = {(x, y) : y = x + 1 and 0 < t =" {(x,">
- neither S nor T is an equivalence relation on R
- both S and T are equivalence relations on R
- S is an equivalence relation on R but T is not
- T is an equivalence relation on R but S is not
33. The perpendicular bisector of the line segment joining P (1, 4) and Q (k, 3) has y−intercept − 4. Then a possible value of k is
- 1
- -4
- 3
- 2
34. The mean of the numbers a, b, 8, 5, 10 is 6 and the variance is 6.80. Then which one of the following gives possible values of a and b?
- a = 0, b = 7
- a = 5, b = 2
- a = 3, b = 4
- a = 2, b = 4
35. The line passing through the points (5, 1, a) and (3, b, 1) crosses the yz−plane at the point (0, 17/2, -13/2) Then
- a = 2, b = 8
- a = 4, b = 6
- a = 6, b = 4
- a = 8, b = 2
36. Let A be a 2 × 2 matrix with real entries. Let I be the 2 × 2 identity matrix. Denote by tr (A), the sum of diagonal entries of A. Assume that A2 = I.
Statement −1: If A ≠ I and A ≠ − I, then det A = − 1.
Statement −2: If A ≠ I and A ≠ − I, then tr (A) ≠ 0.
Statement −1: If A ≠ I and A ≠ − I, then det A = − 1.
Statement −2: If A ≠ I and A ≠ − I, then tr (A) ≠ 0.
- Statement −1 is false, Statement −2 is true
- Statement −1 is true, Statement −2 is true, Statement −2 is a correct explanation for Statement −1
- Statement −1 is true, Statement −2 is true; Statement −2 is not a correct explanation for Statement −1.
- Statement − 1 is true, Statement − 2 is false.
37. The first two terms of a geometric progression add up to 12. The sum of the third and the fourth terms is 48. If the terms of the geometric progression are alternately positive and negative, then the first term is
- -2
- -4
- -12
- 8
38. How many real solutions does the equation x7 + 14x5 + 16x3 + 30x – 560 = 0 have?
- 1
- 4
- 7
- 5
39. The statement p → (q → p) is equivalent to
- p → (p → q)
- p → (p ∨ q)
- p → (p ∧ q)
- p → (p ↔ q)