Electronics-Series-Parallel Circuits

Electronics-Series-Parallel Circuits
1. What theorem replaces a complex network with an equivalent circuit containing a source voltage and a series resistance?
  • Multinetwork
  • Norton
  • Thevenin
  • Superposition
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2. In a series–parallel circuit, individual component power dissipations are calculated using:
  • individual component parameters
  • a percent of the voltage division ratio squared
  • total current squared multiplied by the resistor values
  • a percent of the total power depending on resistor ratios
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3. The current flowing through an unloaded voltage divider is called the:
  • resistor current
  • load current
  • bleeder current
  • voltage current
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4. When a Wheatstone bridge is in a balanced condition, the center voltmeter in the bridge will read:
  • twice the source voltage
  • the same as the source voltage
  • zero volts
  • half the source voltage
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5. When a load is connected to a voltage divider, the total resistance of the circuit will:
  • decrease
  • double
  • increase
  • remain the same
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6. When placed into a circuit, how are electronic components usually connected?
  • positive terminal to positive terminal
  • in parallel
  • as a combination of series and parallel
  • in series
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7. If a Wheatstone bridge is balanced, a voltmeter in the center of the bridge will read:
  • the same as the source voltage
  • half the source voltage
  • zero volts
  • twice the source voltage
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8. The first goal to accomplish in analyzing a complex series-parallel circuit is to
  • equate all parallel components
  • equate all series components
  • solve for all the voltage drops
  • solve for the total current and resistance
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9. If R1 is in series with parallel connected to R2 and R3, what happens to total current if R2 opens?
  • increases
  • decreases
  • remains the same
  • cannot tell
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10. The first goal(s) to accomplish in analyzing a complex series–parallel circuit is to:
  • equate all parallel components
  • equate all series components
  • solve for all the voltage drops
  • solve for the total current and resistance
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